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Analysis of Ammonium Chloride (NH₄Cl)

Class 12 Chemistry Practical

Aim

To analyse the given inorganic salt for one acidic and one basic radical.

Preliminary Test

ExperimentObservationInference
Physical examinationWhite crystalline solid; ammoniacal smellMay be an ammonium salt
SolubilityReadily soluble in waterWater-soluble salt
Dry heatingSalt sublimes; white sublimate on the cooler parts; smell of ammoniaNH₄Cl (sal ammoniac) indicated
Flame testNo characteristic flame colourNot Na⁺, Ca²⁺, Sr²⁺, Ba²⁺, Cu²⁺
Dilute H₂SO₄No characteristic gasCO₃²⁻, S²⁻, SO₃²⁻, NO₂⁻, CH₃COO⁻ absent
Conc. H₂SO₄Colourless pungent gas; white fumes with NH₄OHCl⁻ may be present

Test of Anion (Cl⁻)

ExperimentObservationInference
Heat a pinch of salt with conc. H₂SO₄Colourless gas with a pungent smell; dense white fumes with NH₄OHCl⁻ may be present
Confirmatory Tests
MnO₂ / conc. H₂SO₄
Heat the salt with conc. H₂SO₄ and a pinch of MnO₂
Greenish-yellow chlorine gas is evolvedCl⁻ is indicated
Silver nitrate
Acidify the soda extract with dilute HNO₃ and add AgNO₃, then NH₄OH
Curdy white ppt of AgCl, soluble in NH₄OH, reappears with dilute HNO₃Cl⁻ is confirmed
Chromyl chloride
Heat salt + K₂Cr₂O₇ + conc. H₂SO₄. Pass vapours into NaOH; acidify with acetic acid and add lead acetate
Yellow chromyl chloride vapours; yellow ppt of PbCrO₄Cl⁻ is confirmed (chromyl chloride test)

Ionic equations

  • NaCl + H₂SO₄ (conc.) → NaHSO₄ + HCl ↑
  • MnO₂ + 4HCl → MnCl₂ + Cl₂ ↑ + 2H₂O
  • Ag⁺ + Cl⁻ → AgCl ↓ (white)
  • AgCl + 2NH₄OH → [Ag(NH₃)₂]Cl + 2H₂O

Test of Cation (NH₄⁺)

ExperimentObservationInference
Heat the salt with NaOH solutionAmmoniacal smell; gas turns red litmus blueNH₄⁺ may be present (Group 0)
Bring a glass rod dipped in conc. HCl near the mouth of the tubeDense white fumes of NH₄ClNH₄⁺ may be present
Confirmatory Test
Nessler’s reagent
Pass the gas into Nessler’s reagent (K₂[HgI₄] in KOH)
Brown colouration or brown ppt of basic mercury(II) amidoiodideNH₄⁺ is confirmed. Stop cation analysis here for ammonium salts.

Ionic equations

  • NH₄⁺ + OH⁻ → NH₃ ↑ + H₂O
  • NH₃ + HCl → NH₄Cl (white fumes)
  • 2K₂[HgI₄] + 3KOH + NH₃ → H₂N–Hg–O–Hg–I ↓ + 7KI + 2H₂O

Result

The given salt contains NH₄⁺ as the cation (basic radical) and Cl⁻ as the anion (acidic radical). The salt is Ammonium Chloride (NH₄Cl).

Precautions

  1. Use small quantities of salt and reagents; do not use excess.
  2. Keep the mouth of the test tube away from the face while heating.
  3. Use freshly prepared FeSO₄ for the brown ring test.
  4. Nessler’s reagent is toxic (mercury); handle with care and do not pipette by mouth.

Viva voce

  1. Why does NH₄Cl sublime on dry heating?

    It dissociates to NH₃ and HCl which recombine on the cooler parts of the tube as a white sublimate.

  2. Why is Nessler’s reagent used?

    It gives a characteristic brown ppt with ammonia, confirming NH₄⁺ even in small amounts.

  3. Why is AgNO₃ added after acidifying with HNO₃?

    HNO₃ prevents phosphates, oxalates and carbonates of silver from precipitating; only AgCl / AgBr / AgI ppt.

  4. Why white fumes with a HCl-dipped rod?

    NH₃ + HCl → NH₄Cl smoke.

  5. Why is the chromyl chloride test not given by bromides/iodides?

    They form Br₂ / I₂, not a chromyl compound analogous to CrO₂Cl₂.

  6. Why must the original solution not be made in conc. HCl for NH₄Cl?

    The salt is already a chloride; water extract is enough. Group I HCl is for other cations.

  7. Why does red litmus turn blue with the gas?

    Ammonia is alkaline.

  8. How is NH₄Cl used in Group III?

    NH₄Cl suppresses [OH⁻] by common-ion effect so only Group III hydroxides ppt, not Mg(OH)₂.

अमोनियम क्लोराइड (NH₄Cl) (हिन्दी में)

नमक: अमोनियम क्लोराइड। अम्लीय मूलक: क्लोराइड (Cl⁻)। क्षारीय मूलक: अमोनियम (NH₄⁺)।

गंध अमोनिया जैसी होती है, गंधहीन नहीं। शुष्क ऊष्मा पर नमक उर्ध्वपातित हो जाता है।

क्लोराइड की पुष्टि AgNO₃ से सफेद अवक्षेप (NH₄OH में घुलनशील) से होती है। अमोनियम की पुष्टि नैस्लर अभिकर्मक से भूरे अवक्षेप से होती है।